A system has two charges qA = 2.5 × 10–7C and qB = –2.5 × 10–7 C located at points A: (0, 0, –15 cm) and B: (0,0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system?



The charge at point A, qA = 2.5 × 10–7C


The charge at point B, qB = –2.5 × 10–7 C


the total charge of the system, Qnet = qA + qB


Qnet = 2.5 × 10–7C + (–2.5 × 10–7 C)


Qnet = 0


The distance between these two charges = Distance between point A and B, d = 15 + 15


d = 30 cm = 0.3 m


The electric dipole moment can be defined as the measure of the separation of positive as well as negative charges within a specific system. It tells us about the given system’s overall polarity.


The electric dipole moment of the system, p = qA x d = qb x d


p = 2.5 × 10–7C x 0.3


p = 7.5 x 108 C-m along the positive z-axis


Hence, the electric dipole moment of this system is 7.5 x 108 C-m along the positive z axis.


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