Suppose that the particle in Exercise in 1.33 is an electron projected with velocity v x = 2.0 × 10 6 m s –1 . If E between the plates separated by 0.5 cm is 9.1 × 10 2 N/C, where will the electron strike the upper plate? (| e | = 1.6 × 10 –19 C, m e = 9.1 × 10 –31 kg.)

Question

Philoid · Accepted Answer

Given,

Velocity of the electron, v_x = 2.0 × 10⁶ m s^–1

Separation of plates, l = 0.5cm = 0.5 × 10^-2 m

Electric field between the plates, E = 9.1 × 10² N C^-1

Charge on the electron, q = |e| = 1.6 × 10^-19 C

Mass of the electron, m_e = 9.1 × 10^-31 kg

The vertical deflection of the particle (s) is given by

⇒

⇒ L = √(2.5 × 10^-4) m

hence, L = 1.58 × 10^-2m = 1.58cm

Hence, the electron will strike the upper plate after travelling 1.58cm.

Suppose that the particle in Exercise in 1.33 is an electron projected with velocity vx= 2.0 × 106 m s–1. If E between the plates separated by 0.5 cm is 9.1 × 102 N/C, where will the electron strike the upper plate? (|e| = 1.6 × 10–19 C, me= 9.1 × 10–31 kg.)

Suppose that the particle in Exercise in 1.33 is an electron projected with velocity v_x= 2.0 × 10⁶ m s^–1. If E between the plates separated by 0.5 cm is 9.1 × 10² N/C, where will the electron strike the upper plate? (|e| = 1.6 × 10^–19 C, m_e= 9.1 × 10^–31 kg.)