If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.
Let the current flowing in the circuit be I.
Electromotive force EMF, (E) = 12V
Total resistance in the circuit R = 6 Ω
According to Ohm ’s law, V = IR
Potential drop across 2 Ω resistor = 2 × 2 = 4Volt, as V = I × R by Ohm ’s Law
Potential drop across 1 Ω resistor = 2 × 1 = 2Volt
Potential drop across 3 Ω resistor = 2 × 3 = 6Volt