A galvanometer coil has a resistance of 15 and the metre shows full scale deflection for a current of 4 mA. How will you convert the metre into an ammeter of range 0 to 6 A?
Given:
Resistance of galvanometer coil, G = 15 Ω
Current for full scale deflection, Ig = 4mA
Upper limit of ammeter I = 6A
A galvanometer can detect only small currents and their direction. Thus, to measure large currents it is converted into an ammeter. A galvanometer can be converted into an ammeter by connecting a low resistance called shunt resistance in parallel to the galvanometer
Let shunt resistance = S
We know that value of shunt is given by:
…(1)
By plugging the values of Ig, I and G into Equation (1), we get,
⇒
⇒ S = 10mΩ
For converting the galvanometer into an ammeter of range 0-6 we can add a shunt of resistance 10mΩ.