The magnetic field on the axis of the magnet at a distance d₁ = 14 cm, can be written as:

…………(1)

Where,

M = Magnetic moment

= Permeability of free space

If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.

…………(2)

Equating (1) and (2) we get,

Or,

Or,

Or, d₂ = 14x 0.794 = 11.1cm

The new null points will be located 11.1 cm on the normal bisector.