Suppose the initial charge on the capacitor in Exercise 7 is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?
Given: Capacitance C = 30 uF = 30 × 10 -6F
Inductance L = 27 mH = 20 × 10 -6H
The charge on capacitor, Q = 6 mC = 6 × 10-3C
The diagram is given :
The total energy stored in the circuit can be calculated as followed:
E = 1/2 Q2C
E = 1/2 × (6 × 10-3C)2 × 30 × 10-6F
On calculating, we get
⇒ E = 0.6 J
At later time, total energy will be same i.e. E = 0.6 J as energy is shared between inductor and capacitor.
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