At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m 3 s –1 . If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms –2 ).

Question

Philoid · Accepted Answer

Given: height of water pressure h = 300 m

Height of water flow = 100 m³s^–1

Efficiency of turbine n = 60%

Acceleration due to gravity g = 9.8 ms^–2

Density of water = 10³Kg/m³

The electric power available from the plant is given by the relation:

h × η × р × g × V

substituting the values, we get

300m × 0.6 × 10³ × 9.8ms^–2 × 100 m³s^–1 = 176.4 MW

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms–2).

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m³s^–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms^–2).