The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?
Given: Amplitude of magnetic field part of harmonic electromagnetic wave, B0 = 510 nT
Converting into Tesla, B0 = 510 × 10-9 T
Speed of light in vacuum, c = 3 × 108 m/s
Amplitude of the electric field part of the wave can be calculated by the following expression:
E = c B0
E = 3× 108ms-1 ×510 × 10-9 T
⇒ E = 153 N/C