Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, v = 10 m/s.
Calculate the induced emf in the loop at the instant when x = 0.2 m.
Take a = 0.1 m and assume that the loop has a large resistance.
The emf induced in the coil is given as:
e = B’ av
e =
substituting the given values in above relation, we get
e =
On calculating, we get
e = 5 × 10-5V