The radii of internal and external surface of a hollow spherical shell are 3 cm and 5 cm respectively. It is melted and recast into a solid cylinder of diameter 14 cm. Find the height of the cylinder.

We have,


The internal base radius of spherical shell, r1 = 3 cm,


The external base radius of spherical shell, r2 = 5 cm and


The base radius of solid cylinder, r = 7 cm


Let the height of the cylinder be h


As,


The hollow spherical shell is melted into a solid cylinder;


So,


Volume of solid cylinder = Volume of spherical shell


πr2h =


πr2h =


r2h =


49 × h = (125−27)


h = × 9849


Therefore,


h =


So, the height of the cylinder is .


5