A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of two of these balls are 1.5 cm and 2 cm. Find the radius of the third ball.
Given,
Radius of the spherical ball = 3 cm
After recasting the ball into three spherical balls;
Radius of the first ball = r1 = 1.5 cm
Radius of the first ball = r2 = 2 cm
Let the radius of the third ball be r3 cm.
Then,
Volume of third ball = Volume of spherical ball – volume of 2 small balls
Volume of the third ball = π × 33 –
π
–
π × 23
36π – – 32π/3cm3 = 125π/6cm3
4/3πr3 = 125π/6
r3 = 125π × 3/6 × 4 × π = 125/8
r = = 2.5 cm
Hence, the radius of the third ball is 2.5cm.