A hemisphere of lead of radius 9 cm is into a right circular cone of height 72cm. Find the radius of the base of the cone.
Volume of hemisphere of radius 9 cm
= × π × 9 × 9 × 9cm3
Volume of circular cone (height = 72 cm)
× π × r2 × 72cm
Volume of cone = volume of hemisphere
× π × r2 × 72 =
π × 9 × 9 × 9
r2 = π × 9 × 9 × 9 ×
π = 20.25
r = = 4.5cm
Hence, radius of the base of the cone = 4.5 cm