Water in a canal, 6 m wide and 1.5 m deep, is flowing at a speed of 4 km/hr. How much area will it irrigate in 10 minutes if 8 cm of standing water is needed for irrigation?

Given,


Width of the canal = 6 m


Depth of the canal, = 1.5 m


Length of the cuboid = 666.67 m


Water is flowing at a speed of 4 km/hr = 4000m/hr


Thus,


Area irrigated in 10 minutes = hour = x 4000 = 666.67 m


Hence,


Volume of the water flowing in hour = Volume of the canal


⇒ Volume of the water flowing in hour = 666.67 x 6 x 1.5 = 6000.03 = 60000 m3


Let a m2 is the area irrigated in hour,


Then,


⇒ a × = 6000


⇒ a = m2 = 75000 m2


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