In a corner of a rectangular field with dimensions 35 m × 22 m, a well with 14m inside diameters is dug 8 m deep. The earth dug out is spread evenly over the remaining part of the field. Find the rise in the level of the field.

Question

Philoid · Accepted Answer

Given,

Diameter of the well = 14 m

Radius of the well = 7 m

Height of the well = 8 m

Now,

Volume of the earth dug out of the well = πr²h

= × 7 × 7 × 8 = 1,232 m³

Area on which earth dug out is spread = l × b - r²h

= 35 × 22 - × 7 × 7

= 770 - 154 = 616 m

Level of the earth raised = = 2 m

So, the rise in the level of the field is 2 m.