A rectangular sheet of paper 40 cm × 22 cm, is rolled to form a hollow cylinder of height 40 cm. The radius of the cylinder (in cm) is
Given: Dimensions of rectangular sheet: 40cm × 22cm
Height of the Hollow Cylinder : 40cm
Area of the Rectangle is = length × breadth
Curved surface Area of the Cylinder = 2πrh (where r and h are radius and height of cylinder respectively)
Let a1 be the area of Rectangle
∴ a1 = 40 × 22 cm2
Let a2 be the Curved surface area of Cylinder
∴ a2 = 2 × π × r × 40 cm2
We know that when area of a surface doesn’t change even if its shape is changed.
∴ a1 = a2
⇒ 40 × 22 = 2 × π × r × 40
⇒ r = =
=
=
= 3.5 cm
∴ Radius of the Cylinder is 3.5cm