A mason constructs a wall of dimension (270 cm × 300cm × 350cm) with bricks, each of size (22.5cm × 11.25cm × 8.75cm) and it is assumed that 1/8 space is covered by the mortar. Number of bricks used to construct the wall is

Given: A wall of dimension (270 cm × 300cm × 350cm).


A wall of dimension (22.5cm × 11.25cm × 8.75cm).


space is covered by the mortar.


Here volume of the wall is covered by mortar, 1 – = volume of the wall is covered by bricks.


Volume of the cuboid is given by: lbh (here l, b, h are length , breadth, height respectively).


Let V1 be the volume of the wall.


V1 = l × b × h = 270 × 300 × 350


V1 = 270 × 300 × 350 = 28350000 cm2


Let V2 be the volume of the brick.


V2 = l × b × h = 22.5 × 11.25 × 8.75


V2 = 22.5 × 11.25 × 8.75 = cm2


Let ‘n’ be the number of bricks required to occupy volume of the wall.


n × = 28350000 ×


n = 28350000 × × = 11200


n = 11200


That is 11200 bricks required to occupy volume of the wall.

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