A mason constructs a wall of dimension (270 cm × 300cm × 350cm) with bricks, each of size (22.5cm × 11.25cm × 8.75cm) and it is assumed that 1/8 space is covered by the mortar. Number of bricks used to construct the wall is
Given: A wall of dimension (270 cm × 300cm × 350cm).
A wall of dimension (22.5cm × 11.25cm × 8.75cm).
space is covered by the mortar.
Here 
volume of the wall is covered by mortar, ∴ 1 – 
= 
volume of the wall is covered by bricks.
Volume of the cuboid is given by: lbh (here l, b, h are length , breadth, height respectively).
Let V1 be the volume of the wall.
∴ V1 = l × b × h = 270 × 300 × 350
⇒ V1 = 270 × 300 × 350 = 28350000 cm2
Let V2 be the volume of the brick.
∴ V2 = l × b × h = 22.5 × 11.25 × 8.75
⇒ V2 = 22.5 × 11.25 × 8.75 = 
cm2
Let ‘n’ be the number of bricks required to occupy 
volume of the wall.
∴ n × 
= 28350000 × 
⇒ n = 28350000 × 
× 
= 11200
∴ n = 11200
That is 11200 bricks required to occupy 
volume of the wall.