Given: Diameter of two circular ends of a bucket are 44 cm and 24 cm, and the height of the bucket is 35 cm.

Bucket is in the shape of frustum.

Let V be the Volume of the Bucket(Frustum)

Volume of the frustum is given by: × h × (R² + r² + Rr) (here r and R are the radii of smaller and larger circular ends respectively)

∴ V = × h × (R² + r² + R × r)

⇒ V = × 35 × (22² + 12² + 22 × 12) (diameters are 44 and 24 cm, ∴ their radii are 22cm and 12cm respectively)

⇒ V = × 35 × (484 + 144 + 264) = × 35 × (892)

⇒ V = × 35 × (892) = 32706.6 cm³ = 32.7 litres (∵ 1000cm³ = 1 litre)

∴ The capacity of the bucket is: 32.7 litres