The slant height of a bucket is 45 cm and the radii of its top and bottom are 28 cm and 7 cm respectively. The curved surface area of the bucket is
Given: slant height of a bucket is 45
Radii of its top and bottom are 28 cm and 7 cm respectively.
Bucket is in the shape of a frustum.
Let A be the CSA of the Frustum
CSA of the frustum is given by: πl(r1 + r2) (here l is the slant height and r1 and r2 are the radii of top and bottom of the bucket(frustum))
∴ A = πl(r1 + r2)
⇒ A = π × 45 × (28 + 7) = π × 45 × (35) = 4950 cm2
∴ A = 4950 cm2
That is , curved surface area of the bucket is 4950 cm2