Given: The height of the conical tent is 14m and its floor area is 346.5m².

Canvas of width 1.1m

Surface area of the tent is: πrl

Let be the Surface area of the cone.

Area of the floor is : πr²= 346.5 m²

⇒ πr²= 346.5

⇒ r² = =

⇒ r = √( ) =

⇒ l = √(h² + r²) (here l is the slant height and h , r are height and radius respectively of cone)

⇒ l = √(14² + ()²) = √(196 + ) = √ =

∴ S = πrl = π × =

∴ Area of the canvas required to cover the tent is: m²

∴ l × b = m² (here l is length and b is breadth or width of the canvas)

⇒ l × 1.1 = ( width of the canvas is 1.1m)

⇒ l = = 525m

∴ Length of the canvas required to cover the tent is 525m