The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm respectively. Find the curved surface area of the bucket.

Given: slant height of bucket = l = 45 cm


Radius of bottom circle = r = 7 cm


Radius of top circle = R = 28 cm


As the bucket is in the form of frustum


Formula: Total surface area of frustum = πr2 + πR2 + π(R + r)l cm2


Now we have asked curved surface area, so we should subtract the top and bottom surface


areas which are flat circles.


Surface area of top = πr2


Surface area of bottom = πR2


Curved surface area = total surface area – πr2 - πR2 cm2


= πr2 + πR2 + π(R + r)l – πr2 - πR2 cm2


= π(R + r)l cm2


= 3.14 × (28 + 7) × 45 cm2


= 3.14 × 35 × 45 cm2


= 4945.5 cm2


Therefore, curved surface area of bucket = 4945.5 cm2


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