If (sec θ + tan θ) = m and (sec θ – tan θ) = n, show that mn = 1.

Given: (sec θ + tan θ) = m …………….(1)

(sec θ – tan θ) = n …………….(2)


Multiply equation (1) and (2):


(sec θ + tan θ) (sec θ – tan θ) = mn


(sec2 θ – tan2 θ) = mn


1 = mn ( 1 + tan2 θ = sec2 θ)


Therefore, mn = 1.


Hence, proved.


4