If (sec θ + tan θ) = m and (sec θ – tan θ) = n, show that mn = 1.
Given: (sec θ + tan θ) = m …………….(1)
(sec θ – tan θ) = n …………….(2)
Multiply equation (1) and (2):
(sec θ + tan θ) (sec θ – tan θ) = mn
(sec2 θ – tan2 θ) = mn
1 = mn (∵ 1 + tan2 θ = sec2 θ)
Therefore, mn = 1.
Hence, proved.