If cot θ = 1/√3 write the value of 
Given: cot θ = 1/√3
Thus, tan θ = 1/cot θ = √3
Therefore sec θ = √(1 + tan2 θ)
= √(1 + 3)
= √(4)
= 2
Therefore sec2 θ = 4
Now, cos2 θ = 1/sec2 θ = 1/4
So, consider 
= 
= 
= 
= (3/4)/(5/4)
= 3/5
22
If cot θ = 1/√3 write the value of
Given: cot θ = 1/√3
Thus, tan θ = 1/cot θ = √3
Therefore sec θ = √(1 + tan2 θ)
= √(1 + 3)
= √(4)
= 2
Therefore sec2 θ = 4
Now, cos2 θ = 1/sec2 θ = 1/4
So, consider =
=
=
= (3/4)/(5/4)
= 3/5