sec 70° sin 20° + cos 20° cosec 70° = ?

Consider (sec 70° sin 20°) + (cos 20° cosec 70°)


= (sec (90 – 20)° sin 20°) + (cos 20° cosec (90 – 20)°)


= (cosec 70° sin70°) + (cos 20° sec 20°)


= 1 + 1 ( cosec θ = 1/sin θ and sec θ = 1/cos θ )


= 2

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