If cos (α + β) = 0 then sin (α – β) = ?
We are given that: cos (α + β) = 0
∴We can rewrite it as: cos (α + β) = cos (90° – 0°)
On comparing both sides, we get,
(α + β) = 0 = 90°
⇒ α = 90° – β
Therefore, sin (α – β) = sin (90° – β – β)
= sin (90° – 2β)
= cos 2β