3 cos260° + 2 cot230° – 5 sin245° = ?
Consider 3 cos260° + 2 cot230° – 5 sin245° = 3 (1/2)2 + 2(√3)2 – 5(1/√2)2
= 3(1/4) + 2(3) – 5(1/2)
= (3/4) + 6 – (5/2)
= (3 + 24 – 10)/4
= 17/4