If tan θ = √3, then sec θ = ?
Given: tan θ = √3 = Perpendicular/Base
On comparing, we get:
Perpendicular = √3
Base = 1
Therefore, (Hypotenuse)2 = (Perpendicular)2 + (Base)2
= 3 + 1
= 4
Therefore, hypotenuse = √4
= 2
Therefore sec θ = Hypotenuse/Base
= 2/1 = 2