If sec θ = 25/7, then sin θ = ?
Given: sec θ = 25/7
Therefore, cos θ = 1/sec θ = 7/25 = Base/Hypotenuse
Therefore, on comparing, Base = 7 and Hypotenuse = 25
In a right – angled triangle, (Hypotenuse)2 = (Perpendicular)2 + (Base)2
625 = (Perpendicular)2 + 49
Therefore, Perpendicular = √(625 – 49) = √(576)
= 24
Therefore sin θ = Perpendicular/Hypotenuse
= 24/25