If 3x = cosec θ and 3/x = cot θ, then
Given: 3x = cosec θ , and 3/x = cot θ
Consider 3(x2 – (1/ x2)) =
=
= (1/3)(cosec2 θ – cot2 θ)
= 1/3 (∵ cosec2 x – cot2 x = 1)