If sin θ = √3/2, then (cosec θ + cot θ) = ?
Given: sin θ = √3/2
Therefore, cosec θ = 1/sin θ = 2/√3
cos θ = √(1 – sin2 θ)
= √(1 – (3/4))
= √(1/4)
= 1/2
cot θ = cos θ/sin θ = (1/2)/√3/2
= 1/√3
Therefore, (cosec θ + cot θ) = (2/√3) + (1/√3)
= 3/√3
= √3