If √3 tan θ = 3 sin θ, prove that (sin2 θ – cos2 θ) = 1/3.

Given: √3 tanθ = 3 sinθ






Also, we know,




Now, we need to prove that:


sin2θ – cos2θ = 1/3


L.H.S =


L.H.S =


L.H.S = 1/3


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