If √3 tan θ = 3 sin θ, prove that (sin2 θ – cos2 θ) = 1/3.
Given: √3 tanθ = 3 sinθ
⇒
Also, we know,
Now, we need to prove that:
sin2θ – cos2θ = 1/3
⇒ L.H.S =
⇒ L.H.S = 1/3