If sec 5A = cosec (A – 36°) and 5A is an acute angle, show that A = 21°.

We are given that: sec 5A = cosec (A – 36°)

We can rewrite it as: cosec (90° – 5A) = cosec (A – 36°)


On comparing both sides, we get,


90° – 5A = A – 36°


A + 5A = 90° + 36°


6A = 126°


A = 21°


Hence, proved.


20