Construct a ΔABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are 3/4 times the corresponding sides of ΔABC.
Steps of Construction:
1. First, we draw a triangle ABC of given dimensions.
2. Draw a line segment BC of length 7cm.
3. From B, make an angle of 60° and draw a ray from B.
4. Now taking B as center and radius of 6cm(length of AB), draw an arc on the ray. The point is A.
5. Join AC.
6. Now we have to make a triangle which is 3/4 times of this triangle.
7. Draw a ray BZ making an acute angle with the line BC. Make 4 equal arcs starting from B then B1 and so on till B4.
8. Join B4C. Draw a line from B3 parallel to B4C cutting BC at C’.
9. Draw another line from C’ parallel to CA cutting AB at A’.
10. A’BC’ is our required triangle,