Construct a ΔABC in which AB = 6 cm, ∠A = 30° and ∠B = 60°. Construct another ΔAB' C' similar to ΔABC with base AB' = 8 an.
Steps of Construction:
1. Draw a line AB of length 6cm and extend it to B’ such that AB’ is of length 8 cm.
2. Make an angle of 30° from A and angle of 60° from B. The point where these extended rays meet is C.
3. As angles are equal in similar triangles, make an angle of 60° from B’ as well.
4. Extend the line AC along C such that it cuts the ray from B’ at C’.
5. AB’C’ is the required triangle .