Construct a ΔABC in which AB = 6 cm, A = 30° and B = 60°. Construct another ΔAB' C' similar to ΔABC with base AB' = 8 an.

Steps of Construction:


1. Draw a line AB of length 6cm and extend it to B’ such that AB’ is of length 8 cm.


2. Make an angle of 30° from A and angle of 60° from B. The point where these extended rays meet is C.



3. As angles are equal in similar triangles, make an angle of 60° from B’ as well.


4. Extend the line AC along C such that it cuts the ray from B’ at C’.



5. AB’C’ is the required triangle .


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