In the given figure, PA and PB are tangents to a circle such that PA = 8 cm and APB = 60˚. The length of the chord AB is

In Δ PAB,


APB = 60° and PA = 8 cm [given]


PB = PA = 8 cm


[ tangents drawn from an exterior point to the circle are equal in length]


PAB = PBA = θ [LET]


Now, In Δ PAB


APB + PAB + PBA = 180° [ Sum of all the angles of a Δ is 180°]


60° + θ + θ = 180°


60° + 2θ = 180°


2θ = 120°


θ = 60°


Thus, Δ PAB is an equilateral Triangle.


Length of chord AB = 8 cm.

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