Solve: a2b2x2 – (4b4 – 3a4) x – 12a2b2 = 0.
The given quadratic equation is –
a2b2x2 –(4b4 – 3a4) x – 12a2b2 = 0
Discriminant D of the quadratic equation ax2 + bx + c = 0 is given by –
D = b2 – 4ac
Comparing the equation ax2 + bx + c = 0 with given quadratic equation is a2b2x2 –(4b4 –3a4) x – 12a2b2 = 0,we get –
a = a2b2 , b = –(4b4 – 3a4) and, c = – 12a2b2
∴ The roots of the given quadratic equation is given by –
Thus, the roots of the given quadratic equation are (4b2/a2) and (– 3a2/b2).