fig.17

Let the radius of the circular park be r meters.

Given –

Circumference of circular park = 352 m

⇒ 2 × π × r = 352

⇒ 2 × (22/7) × r = 352

⇒ r = (7/44) × 352

∴ r = 7 × 8 = 56 m

⇒ outer radius = 56 + 7 = 63 m

∴ Area of the road = π(63² – 56²)

= (22/7)(63 + 56)(63 – 56)

= (22/7)(119)(7)

= 22 × 119

= 2618 m²