Puja works in a bank and she gets a monthly salary of ₹ 35000 with annual increment of ₹ 1500. What would be her monthly salary in the 10th year?

Given –


Monthly Salary = Rs. 35000


Annual Salary = Rs. (12 × 35000) = Rs. 420000


Annual Increment = Rs. 1500


Let us consider this situation as an AP with


first term = a = Rs. 420000


and, Common Difference = d = Rs. 1500


Salary in 10th year is given by –


a10 = a + (10 – 1)d = 420000 + 9 × 1500 = Rs. 433500


Thus, Monthly Salary in 10th year = Rs. (433500/12)


= Rs. 36125


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