Puja works in a bank and she gets a monthly salary of ₹ 35000 with annual increment of ₹ 1500. What would be her monthly salary in the 10th year?
Given –
Monthly Salary = Rs. 35000
∴ Annual Salary = Rs. (12 × 35000) = Rs. 420000
Annual Increment = Rs. 1500
Let us consider this situation as an AP with
first term = a = Rs. 420000
and, Common Difference = d = Rs. 1500
∴ Salary in 10th year is given by –
a10 = a + (10 – 1)d = 420000 + 9 × 1500 = Rs. 433500
Thus, Monthly Salary in 10th year = Rs. (433500/12)
= Rs. 36125