Or, which term of the AP 3, 15, 27, 34, … will be 132 more than its 54th term?

Which term of the AP 3, 15, 27, 39, … will be 132 more than its 54th term.

Given AP = 3, 15, 27, 39, …


First term, a = 3


Common difference, a2 - a1 = 15 - 3 = 12


And we know


Nth term of an AP, an = a + (n - 1)d


Where a is first term and d is common difference.


Now, let the mth term be 132 more than 54th term


In that case,


am = a54 + 132


a + (m - 1)d = a + 53d + 132


(m - 1)12 = 53(12) + 132


12m - 12 = 636 + 132


12m = 768 + 12


12m = 780


m = 65


hence, 65th term will be 132 more than its 54th term.


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