Two dice are thrown at the same time. Find the probability that the sum of two numbers appearing on the top of the dice is more than 9.

When two dice are thrown, the possible outcomes are


{(1,1) (1,2) (1,3) (1,4) (1,5) (1,6), (2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1) (3,2) (3,3) (3,4) (3,5) (3,6), (4,1) (4,2) (4,3) (4,4) (4,5) (4,6), (5,1) (5,2) (5,3) (5,4) (5,5) (5,6), (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}


The outcomes in which sum of no's is 9 are ={(3,6) (4,5) (5,4) (6,3)}


No of Total possible outcomes = 36


No of favourable outcomes = 4


And, Probability of an event


Therefore,


P(Getting sum 9)


33