It is given that the relation in the set N given by

R = {(a, b): a = b – 2, b > 6}

Now, b > 6, (2, 4) ∉ R

Also, as 3 ≠ 8 – 2, (3, 8) ∉ R

And 8 ≠ 7 – 2

Therefore, (8,7) ∉ R

Now, consider (6,8)

We have 8 > 6 and also 6 = 8 - 2

Therefore, (6, 8) ϵ R.