In each of the following cases, state whether the function is one-one, onto or bijective. Justify your answer.
f : R → R defined by f (x) = 3 – 4x
It is given that f : R → R defined by f (x) = 3 – 4x
Let x1, x2ϵ R such that f(x1) = f(x2)
⇒ 3 – 4x1 = 3 – 4x2
⇒ -4x1 = -4x2
⇒ x1 = x2
⇒ f is one- one
For any real number (y) in R, there exist in R such that
⇒ f is onto.
Therefore, function f is bijective.