10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be:
16mL Explanation: Since 10 mL of NaOH solution requires 8 mL of HCl solution. Therefore, 20 mL of NaOH solution will require 8 x 2 = 16 mL of HCl solution.