Find the values of k so that the function f is continuous at the indicated point in Exercises 26 to 29.

It is given that ![]()
Also, it is given that function f is continuous at x = 5,
So, if f is defined at x = 5 and if the value of the f at x = 5 equals the limit of f at x = 5.
We can see that f is defined at x = 5 and
f(5) = kx + 1 = 5k + 1
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⇒ ![]()
⇒ 5k + 1 = 15 -5 = 5k + 1
⇒ 5k + 1 = 10
⇒ 5k = 9
⇒ k = ![]()
Therefore, the required value of k is
.