Find the values of k so that the function f is continuous at the indicated point in Exercises 26 to 29.
It is given that
Also, it is given that function f is continuous at x = 5,
So, if f is defined at x = 5 and if the value of the f at x = 5 equals the limit of f at x = 5.
We can see that f is defined at x = 5 and
f(5) = kx + 1 = 5k + 1
⇒
⇒ 5k + 1 = 15 -5 = 5k + 1
⇒ 5k + 1 = 10
⇒ 5k = 9
⇒ k =
Therefore, the required value of k is.