If 
, find k so that A2 = kA – 2I
A2 = A.A 
Now, A2 = kA – 2I
Comparing the corresponding elements, we get,
3k -2 = 1
⇒ 3k = 3
⇒ k = 1
Therefore, the value of k is 1.
20
If , find k so that A2 = kA – 2I
A2 = A.A
Now, A2 = kA – 2I
Comparing the corresponding elements, we get,
3k -2 = 1
⇒ 3k = 3
⇒ k = 1
Therefore, the value of k is 1.