Using elementary transformations, find the inverse of each of the matrices.
First of all we need to check whether the matrix is invertible or not. For that-
For the inverse of a matrix A to exist,
Determinant of A ≠ 0
Here ∣A∣ = (1)(3) – (-1)(2) = 5
So the matrix is invertible.
Now to find the inverse of the matrix,
We know AA-1 = I
Let’s make augmented matrix-
→ [ A : I ]
Apply row operation- R2→ R2 – 2R1
→
Apply row operation- R2→ R2/5
→
Apply row operation- R1→ R1 + R2
→
The matrix so obtained is of the form –
→ [ I : A-1 ]
Hence inverse of the given matrix-
→