Find the second order derivatives of the function

x3 log x

Let us take y = x3 log x

Now,




= logx.3x2 + x3.1/x


= logx .3x2 + x2


= x2(1 + 3logx)


Therefore,





= 2x + 6xlogx + 3x


= 5x + 6xlogx


= x(5 + 6logx)


7