If y = Aemx + Benx, show that
According to given equation, we have,
y = Aemx + Benx
Then,
= Amemx + Bnenx
Now, on again differentiating we get,
= Am2emx + Bn2enx
= Am2emx + Bn2enx – (m+n)( Amemx + Bnenx) + mn(Aemx + Benx)
= Am2emx + Bn2enx- Am2emx - Bmnenx -Amnemx - Bn2enx + Amnemx + Bmnenx
= 0
Hence Proved