If y = Aemx + Benx, show that

According to given equation, we have,

y = Aemx + Benx


Then,




= Amemx + Bnenx


Now, on again differentiating we get,





= Am2emx + Bn2enx



= Am2emx + Bn2enx – (m+n)( Amemx + Bnenx) + mn(Aemx + Benx)


= Am2emx + Bn2enx- Am2emx - Bmnenx -Amnemx - Bn2enx + Amnemx + Bmnenx


= 0



Hence Proved


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