If y = (tan–1 x)2, show that (x2 + 1)2 y2 + 2x (x2 + 1) y1 = 2

: It is given that

y = (tan–1 x)2


On differentiating we get,






Again differentiating, we get,




So, (1+x2)2y2 + 2x(1+x2)y1 = 2


where,


Hence Proved


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