Find area of the triangle with vertices at the point given in each of the following:

(1, 0), (6, 0), (4, 3)

Given vertices of the triangle are (1, 0), (6, 0), (4, 3)

Let the vertices of the triangle be given by (x1, y1), (x2, y2), (x3, y3)


Area of triangle is given by Δ =


Area of triangle = Δ =


Expanding the determinant along Row 1


Δ = 1/2 × [1 × (0 × 1 – 3 × 1) – 0 × (6 × 1 – 4 × 1) + 1 × (6 × 3 – 4 × 0)]


Δ = 1/2 × [1 × (0 – 3) – 0 + 1 × (18 – 0)]


Δ = 1/2 × (-3 + 18) = 15/2 sq. units


Δ = 15/2 sq. units = 7.5 sq. units


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