Find the intervals in which the following functions are strictly increasing or decreasing:
6 – 9x – x2
It is given that function f(x) = 6 – 9x – x2
f’(x) = -9 – 2x
If f’(x) = 0, then we get,
⇒ x = ![]()
So, the point x = 
 divides the real line into two disjoint intervals,
![]()
So, in interval![]()
f’(x) = -9 – 2x > 0
Therefore, the given function (f) is strictly increasing for x < 
.
And in interval![]()
f’(x) = -9 – 2x < 0
Therefore, the given function (f) is strictly decreasing for x>
.
Thus, f is strictly decreasing for x>
.